Posted: June 25th, 2022
Substituting y’s value in the 2nd equation to the 1st equation
The linear equation is therefore not solvable.
Multiply equation 1 by 5, equation 2 by 2, and subtract r to eliminate r.
3.Using the cramer’s rule D=(30 6)
The determinant is a= -5.-6 – -11.6=96
2 -11) The determinant=30.-11-2.-5=b=-320
Factorise 1/v to cancel out the one on the right side
Divide by the LCM = N2-12n = 8n48/n2-12n
Cross multiplying: (n+1), (n2-12n)= (8n48) (n2-12n)
n2-12 and n will cancel each other
Multiply equation 1 by 14, and equation 2 by 4 to eliminate
S= Price of each strawberry =$12
P=Price per peacan=8
Multiplying the 2nd equation by 3 will eliminate
S=price for eeach strawberry=$19
P = Price of each New York = $15
Multiply 2nd equation with 15 to get rid of x
$18750 = y=money in government-insured bonds
x = money in non-insured bond=$31250
b) Revenue function =600x=(500000+200x).
Tickets X = 23
TRUE-e.g multiply equations x+y=8 and 2
The solution will be different from 8-16
FALSE- Elimination is a method which eliminates the leading variable from the first equation of each equation, but not by replacing it with the sum of the equations.
TRUE – A system of equations with two variables can or may not provide solutions
TRUE – The marginal cost of an equation with a linear cost is a variable m.
TRUE – An Inconsistence System is a set of linear equations that contains equations without a solution.
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